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FMB Chatbox
PMR - Mathematics question no.4
4 posters
Page 1 of 1
Cikgu Edy- Moderator
- Number of posts : 968
Humor : hiiii hiii . nobody's perfect laa...
Registration date : 08/05/2008
Re: PMR - Mathematics question no.4
by Cikgu Edy Tue May 20, 2008 5:07 pm
Tips menjawab soalan di atas...
= 2(Y x Y x Y) [1 - (Y) ]
= gantikan Y dengan -1
= .... cuba teruskan... nanti cikgu bantu... jangan takut untuk menjawab sebab lebih baik salah menjawab pada ketika ini daripada salah menjawab semasa peperiksaan besar nanti...
selesaikan yang berwarna biru terlebih dahulu.
= 2(Y x Y x Y) [1 - (Y) ]
= gantikan Y dengan -1
= .... cuba teruskan... nanti cikgu bantu... jangan takut untuk menjawab sebab lebih baik salah menjawab pada ketika ini daripada salah menjawab semasa peperiksaan besar nanti...
selesaikan yang berwarna biru terlebih dahulu.
Cikgu Edy- Moderator
- Number of posts : 968
Humor : hiiii hiii . nobody's perfect laa...
Registration date : 08/05/2008
Re: PMR - Mathematics question no.4
by syahrom Sun Aug 02, 2009 8:59 am
the answer is C=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)]
=2[1-(-1)]
=[2+(-2)]
=[2-2]
=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)]
=2[1-(-1)]
=[2+(-2)]
=[2-2]
=0
syahrom- MBF New Member
- Number of posts : 2
Registration date : 02/08/2009
Re: PMR - Mathematics question no.4
by Cikgu Edy Mon Aug 03, 2009 12:37 pm
syahrom wrote:the answer is C=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)] ....ok
=2[1-(-1)].... semak semula, bukan begini caranya....
=[2+(-2)]
=[2-2]
=0
lihat komen warna biru
terimakasih kerana menjawab, silalah buat lagi supaya cikgu dapat membantu...
Cikgu Edy- Moderator
- Number of posts : 968
Humor : hiiii hiii . nobody's perfect laa...
Registration date : 08/05/2008
adah- MBF New Member
- Number of posts : 2
Registration date : 01/10/2009
Re: PMR - Mathematics question no.4
by Cikgu Edy Tue Oct 06, 2009 8:19 am
adah wrote:agak susa soklan nii
cuba saja... nanti cikgu akan komen....
Cikgu Edy- Moderator
- Number of posts : 968
Humor : hiiii hiii . nobody's perfect laa...
Registration date : 08/05/2008
Re: PMR - Mathematics question no.4
by nurizni Tue Jul 20, 2010 3:09 am
jawapan saya
B. -4
if y=-1 , then 2y³(1-y)
= 2(-1)³(1-(-1)
= 2 (-1)(1+1)
= 2 x -1 x 2
= -2 x 2
= -4
it right?
B. -4
if y=-1 , then 2y³(1-y)
= 2(-1)³(1-(-1)
= 2 (-1)(1+1)
= 2 x -1 x 2
= -2 x 2
= -4
it right?
nurizni- MBF New Member
- Number of posts : 11
Age : 29
Registration date : 27/06/2010 -
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